What will happen if we join two two terminals of a electric cell with directly through a wire?
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The current will not pass through the wire
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Battery is the source of potential difference and wire is a conductor but can't be a perfect conductor. It has some resistance in which voltage gets dropped. The connection of wire to battery makes the circuit as shown below-
And whenever battery is connected with resistance as shown above , it drives some current (I)=V/R.
where V=potential difference of the battery
,I=current flowing through circuit, R=resistance of wire .
As resistance of wire is much smaller so it will be large amount of current through battery and battery will get discharged much sooner.
And connected wire will get heated . According to joule's law of heating effect , energy will be given as E=(I^2 )*R*t=(V^2 /R)*t.
here, t =time duration of flow of current.
Because of low value of R at some potential differnce(V) of battery , ratio (V^2 /R) will have large value . It indicates the large value of energy dissipating rate.
And whenever battery is connected with resistance as shown above , it drives some current (I)=V/R.
where V=potential difference of the battery
,I=current flowing through circuit, R=resistance of wire .
As resistance of wire is much smaller so it will be large amount of current through battery and battery will get discharged much sooner.
And connected wire will get heated . According to joule's law of heating effect , energy will be given as E=(I^2 )*R*t=(V^2 /R)*t.
here, t =time duration of flow of current.
Because of low value of R at some potential differnce(V) of battery , ratio (V^2 /R) will have large value . It indicates the large value of energy dissipating rate.
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