Question

what will happen to the area of a square when (a) its side is doubled . (b) its side is halved.

Answer 1

$let \: side \: be \: s \\ case \: 1 \\ when \: side \: is \: doubled \\ side = 2s \\ area = (side) {}^{2} \\ area = (2s) {}^{2} \\ area = 4 {s}^{2} \\ area \: will \: become \: 4 \: times \\ case \: 2 \\ when \: side \: is \: halved \\ side = \frac{s}{2} \\ area =(side) {}^{2} \\ area = ( \frac{s}{2} ) {}^{2} \\ area = \frac{s {}^{2} }{4} \\ hope \: it \: helps \\ please \: mark \: it \: as \: brainliest$