Question

What will happen to the current passing through the resistance, if the potential difference across it is doubled and the resistance is halved

Answer 1

let the current in first case be 'I', potential diff. 'V' and resistance 'R'
so... by Ohm's law I=V/R...


now in second case potential diff. is 2V and resistance is R/2 now applying ohm's law
I' =4V/R.....
substituting it we get,
I'=4I

it shows that new current is four times of old one




hope it helped...
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