Question

What will happen to the curved surface area and the volume of the cylinder if the radius is
tripled and its height is halved​

Answer 1

New area will be 1.5 times and new volume will be 4.5 times

Step-by-step explanation:

Let the radius pf the cylinder is r and height is h

Curved surface area of cylinder is given by

$A=2\pi rh$

And volume is given by $V=\pi r^2h$

Now in new case radius is tripped so new resistance = 3r

And height is halved so new height = $\frac{h}{2}$

So new area will be equal to $A_{new}=2\pi (3r)\frac{h}{2}=1.5A$

So area will be 1.5 times of previous area

Now $V_{new}=\pi (3r)^2\frac{h}{2}=4.5\pi r^2h=4.5V$

So new volume will be 4.5 times of previous volume

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