What will happen to the gravitational force between 2 bodies if they are brought closer by half of their initial separation?
Answers
Answered by
20
we know F = product of two masses/square of distance between them.
therefore F1 = m1.m2/r²
now we half the distance.
new force F2 = m1.m2/ (r/2)²
= m1.m2/ r²/4
= 4 × m1.m2/r²
= 4 × F1
therefore force will be 4 times the original
therefore F1 = m1.m2/r²
now we half the distance.
new force F2 = m1.m2/ (r/2)²
= m1.m2/ r²/4
= 4 × m1.m2/r²
= 4 × F1
therefore force will be 4 times the original
Answered by
6
Answer:
Increases 4 times
Explanation:
F = Gm1m2/r^2 ---1
when distance is reduced to half,
r₀ = r/2
F₀ = Gm1m2/r₀^2
= Gm1m2/(r/2)^2
= Gm1m2/r^2/4
F₀ = 4Gm1m2/r^2 ---2
Therefore,
Gm1m2/r^2 = F
Comparing 1 and 2
F₀ = 4Gm1m2/r^2
F₀ = 4F
Hence, the new force will be 4 times the original force.
Hope this answer helps you.
If this answer helps you make me the brainliest.
Similar questions