Question

What will happen to the time period of a simple pendulum if its length is doubled ?

Answer 1

time period of a simple pendulun is given by,
$T=2 \pi \sqrt{ \frac{1}{g} }$
$T \alpha \sqrt{l}$....................1
l'= 2l
$T' \alpha \sqrt{l'}$
$T' \alpha \sqrt{2l}$...................2
DEVIDING 1 AND 2
$\frac{T}{T'} = \frac{ \sqrt{l}}{ \sqrt{2l} }$
$\frac{T}{T'} = \frac{ 1}{ \sqrt{2l} }$
$T'= \sqrt{2} T$

Answer 2

the time period will increase