Question

what will happen to the total surface area of a cube if its edge is reduced to half?​

Answer 1

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Answer 2

let initial length of edge of cube be a

so TSA of cube is =Area1

$6 {a}^{2} \: unit \: square$

but, now edge is halved so

A=a/2

so TSA of new cube =Area2

$= 6 { \frac{a}{2} }^{2} \\ \\ = 6 { \frac{a}{4} }^{2} \\ \\ = \frac{3 {a}^{2} }{2} unit \: square$

now ratio,

$= \frac{area1}{area2} \\ \\ = \frac{6 {a}^{2} }{ \frac{3 {a}^{2} }{2} } \\ \\ = \frac{4}{1}$

So new area becomes 4 times smaller than previous one