What will happen to the volume of a cylinder of its radius is double and height is halved
Answers
Answered by
9
Radius = r
Height = h
Volume = V = πr^2h
====================
New Radius = r' = 2r
New Height = h' = h/2
_______________
New Volume = V'
= πr'^2h'
= π(2r)^2×(h/2)
= π×4×r^2×h/2
= 2× (πr^2h)
V' = 2 V
__________________
Hence the volume will get doubled if it's Radius is been doubled and height is been halved.
Height = h
Volume = V = πr^2h
====================
New Radius = r' = 2r
New Height = h' = h/2
_______________
New Volume = V'
= πr'^2h'
= π(2r)^2×(h/2)
= π×4×r^2×h/2
= 2× (πr^2h)
V' = 2 V
__________________
Hence the volume will get doubled if it's Radius is been doubled and height is been halved.
Answered by
6
Let the original radius be 'r' and height be 'H'.
Volume of original cylinder=πr²h.
Now, increased radius=2r and height=1/2h
Volume=π{2r}²×1/2h=2πr²h
Therefore we can say that the volume doubled.
Hope it helps you...
Please mark as brainliest answer!!!
Volume of original cylinder=πr²h.
Now, increased radius=2r and height=1/2h
Volume=π{2r}²×1/2h=2πr²h
Therefore we can say that the volume doubled.
Hope it helps you...
Please mark as brainliest answer!!!
rukuraj77:
Thank u
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