Question

what will happen when 'an' goes on increasing options x tends to a, x tends to n, x tends to infinity, x tends to 0

Answer 1

Answer:

At x = 0, each fn(x) = 0, so that the sum of the series f(0) = 0. For x ≠ 0 ,thus Mn does not tend zero as n→∞.Since an(x) tends uniformly to zero, therefore for any ε > 0, there exists an.

Step-by-step explanation:

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