CBSE BOARD X, asked by DesperateStudent, 11 months ago

what will I do in case a trigonometric question includes tan 90° or any other trigonometric ratio that is not defined and I have to add to some other trignomstric ratio.For example
 \frac{ \sin(90) }{ \csc(30 ) }  +  \frac{ \tan(45) }{ \sec(90) }



Answers

Answered by chirag2k17
1

Answer:

You will have to put is actual value that is 1/0 and then solve

Explanation:

solving question:

=sin(90)/cosec(30)  +  tan(45)/sec(90)

=1/2 + 1/(1/0)

=1/2 + 1*0/1

=1/2+0

=1/2

hope you will find it helpful, please mark it as brainliest if you do so.

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