What will its temperature be ten minutes into the experiment?
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Assuming heater is supplying heat at uniform rate of
Q
˙
cal/s
in 10 minutes total heat transferred =600×
Q
˙
This amount should be equal to heat gained by water =mcΔT where m is mass of water and c is specific heat capacity of water.
mcΔT=600
Q
˙
m×1calg
−1
C
∘
−1
×(100−0)=600
Q
˙
⇒
Q
˙
=
6
m
...(i)
The heater supplies heat at constant temperature to convert water into steam, the amount of heat is given by
55minutes×60×sec×
Q
˙
..(i)
this amount should be equal to heat gained by water to convert into steam at constant temperature =mL where L is latent heat of vaporization
3300
Q
˙
=mL...(ii)
substituting value of
Q
˙
from equation (i)
3300
6
m
=mL
L=550cal/g
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