Question

what will the amount of rs 10000 became after 2 year at the rate of 9% compound interest per annum

Answer 1

Answer:

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Step-by-step explanation:

A = P(1 + R/100)^n

A = 10,000(1 + 9/100)^2

A = 11,881 rs

I = A - P

I = 1,881 rs.

Answer 2

Step-by-step explanation:

10000(1+9÷100)hole sqaure

=10000(109÷100)hole square

=10000×109/100×109/109

=109×109=11881