what will the perimeter of a rectangle be if its length is 3 times its breadth and the length of diagonal is 8√10cm? please provide explanation
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answer is- let breath=x and length=3x given that diagonal=8+10=V640 we know that by Pythagoras theorem
(V640)^2=x^2+3x^2
640=x^2+9x^2
640=10x^2
64=x^2
8=x
hence sides are8and24
perimeter=2(24+8)
perimeter=64
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