Question

What will the power of that motor which lift water 1000 litre into a tank in 30 minutes by the height of 10metre calculate the power of moter in watt

Answer 1

Answer:

Volume of water = 30 m3. Density of water = 1000 kg/m3, Mass of water m = Volume X Density = 30 x 1000 kg = 30000 kg Height of the tank above the ground h = 40 m Potential energy of water = mgh = 30,000 x 9.8 x 40 J (g = 9.8 m/s2) = work done in lifting the water to a height of 40 m Power required to lift the water Pr = work done / time = mgh/t = 30,000 x 9.8 x 40 J /(15 x 60 s) = [30,000 x 9.8 x 40/(15 x 60)] W Le P be the power consumed. Only 30% of the power P is utilized in lifting the water up. So 30P/100 = Pr Therefore P = 100Pr/30 = (100/30) x [30,000 x 9.8 x 40/(15 x 60)] W = 43.6 kW

Answer 2

Answer:

3000000w....

Explanation:

p=w/t

Therefore, work done=mgh

mass=vol.×density

=30×1000 = 30000kg

therefore, work done = mgh

=30000×10×10

=30000×100

=3000000w