What will the the answer to this question be?
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sin^2y + cosxy=k
differentiate wrt x
sin2y(dy/dx)-sinxy(y+xdy/dx)=0
(dy/dx)(sin2y-xsinxy) =ysinxy
dy/dx=ysinxy/(sin2y-xsinxy)
at x=1,y=π/4
dy/dx=(π/4)(1/√2)/(1-(1/√2))
differentiate wrt x
sin2y(dy/dx)-sinxy(y+xdy/dx)=0
(dy/dx)(sin2y-xsinxy) =ysinxy
dy/dx=ysinxy/(sin2y-xsinxy)
at x=1,y=π/4
dy/dx=(π/4)(1/√2)/(1-(1/√2))
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