Math, asked by navitachopra80p9ra3w, 1 year ago

what will the value of the equation

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Answered by sadananda80palw5y
1
(z+1/z)^2=z^2+1/z^2+2
(z+1/z)^2=34+2
(z+1/z)^2=36
z+1/z=√36
z+1/z=6

(z+1/z)^3=z^3+1/z^3+3(z+1/z)
216=z^3+1/z^3+3×6
216=z^3+1/z^3+18
216-18=z^3+1/z^3
198=z^3+1/z^3
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