what will the volume of the gas if the pressure is charged to 2 atm under the same condition
Answers
volume will be V/2............
Answer:
P∝T or P=constant×T or P=k×T
where ∝ means “is proportional to,” and k is a proportionality constant that depends on the identity, amount, and volume of the gas.
For a confined, constant volume of gas, the ratio \displaystyle \frac{P}{T}
T
P
is therefore constant (i.e., \displaystyle \frac{P}{T}=k
T
P
=k ). If the gas is initially in “Condition 1” (with P = P1 and T = T1), and then changes to “Condition 2” (with P = P2 and T = T2), we have that \displaystyle \frac{{P}_{1}}{{T}_{1}}=k
T
1
P
1
=k and \displaystyle \frac{{P}_{2}}{{T}_{2}}=k,
T
2
P
2
=k, which reduces to \displaystyle \frac{{P}_{1}}{{T}_{1}}=\frac{{P}_{2}}{{T}_{2}}.
T
1
P
1
=
T
2
P
2
. This equation is useful for pressure-temperature calculations for a confined gas at constant volume. Note that temperatures must be on the kelvin scale for any gas law calculations (0 on the kelvin scale and the lowest possible temperature is called absolute zero). (Also note that there are at least three ways we can describe how the pressure of a gas changes as its temperature changes: We can use a table of values, a graph, or a mathematical equation.)