Question

what will you observe if nickel strip is replaced by iron strip​

Answer 1

Answer:

At anode : Ni→Ni

2+

+2e

−

At cathode : [Ag

+

+e

−

→Ag]×2

Cell reaction : Ni+2Ag

+

→Ni

2+

+2Ag

E

cell

∘

=E

cathode

∘

−E

anode

∘

=E

Ag

+

/Ag

∘

−E

Ni

2+

/Ni

∘

=0.80V−(−0.25V)

E

cell

∘

=1.05V

ii. E

cell

=E

cell

∘

−

n

0.059

log

[Ag

+

]

2

[Ni

2+

]

Here , n=2,E

cell

∘

=1.05V,[Ni

2+

]=0.1M,[Ag

+

]=1.0M

E

cell

=1.05V−

2

0.059

log

(1)

2

(0.1)

E

cell

=1.05V−0.0295log10

−1

=1.05+0.0295V=1.0795V