what will you observe when dilute hydrochloric acid is added to a small amount of copper oxide in a beaker
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2HCL + CuO -----> CuCl2 + H2O
the CU replaces the H part.....Cu is brown in color..n HCl is colorless..!! n CuCl2 is blue-green.. in color..n water again colorless..hope this helps..!!:)
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the CU replaces the H part.....Cu is brown in color..n HCl is colorless..!! n CuCl2 is blue-green.. in color..n water again colorless..hope this helps..!!:)
Mark as brainliest
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