Physics, asked by eyasumuler75, 11 months ago

what work is done by a force F=2Ni+3Nj,that moves a particle from a position ri=2mi+3mj to a position rf=-4mi-3mj

Answers

Answered by safnahakkim

4

Answer:WORK DONE=F.S

F=2i+3j

S=displacement vector

S=rf-ri=-6i-6j

so work done=(2i+3j).(-6i-6j)=-12i-18j

Explanation:if it gelps mark as brainliest

Answered by vishnu779900

0

Answer:

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Explanation:

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