what work is required to bring q=3uc originally a distance of 1.5m from a charge Q=20uc until it is 0.50m away?
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sry I didn't get the answer to that question
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Answer:
0.72J
Explanation:
W=∆U =kqQ( 1/0.5 - 1/1.5)
=k × 3 × 20 × 10^-12 ( 2- 2/3 )
= k× 80 × 10^-12
=0.72 J
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