what work will be done when 3 mole of an ideal gas is compressed to half the initial volume at constant temperature of 300 Kelvin
Answers
Since, the process is occurring at an constant temperature, thus the process is ISOTHERMAL.
Work done = 2.303nRTlogV₂/V₁
where n is the no. of moles, R is the universal constant of gas, T is the temperature at which the work done is measured, and V₂ is the final volume and V₁ is the initial volume.
Let V₁ = 2V, then V₂ = V
Thus,
Work done = 2.303 × 3 × 8.31 × 300 × log(V/2V)
∴ Work done = 17224.137 × [0 - log2]
∴ Work done = -5184.47 J. = -5.184 kJ.
Hence, work done by us on gas = -5.184 kJ.
In Physics, work done will be -ive only, in this case.
''But in Chemistry, work done will be +ive. It is an convection. You need to learn that. There is no perfect reason for it except the thinking of different scientists. ''
Hope it helps.
Answer:
Work done = 2.303nRTlogV₂/V₁
where n is the no. of moles, R is the universal constant of gas, T is the temperature at which the work done is measured, and V₂ is the final volume and V₁ is the initial volume.
Let V₁ = 2V, then V₂ = V
Thus,
Work done = 2.303 × 3 × 8.31 × 300 × log(V/2V)
∴ Work done = 17224.137 × [0 - log2]
∴ Work done = -5184.47 J. = -5.184 kJ.
Hence, work done by us on gas = -5.184 kJ.
In Physics, work done will be -ive only, in this case.