What would b
that would be [H+] of 0.006 M benzoic acid (K = 6 x10-5)
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43
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Explanation:
I hope u will understand it
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8
Answer:
answer is 2rd option that is 6x10^(-4)
Explanation:
As we know that
C = 0.006 M
K = 6 x 10(-5)
we know that to calculate H+ the formula is given below
H+ = Sqr
so by placing values in it
H+ = Sqr root ( K*C)
by putting values
H+= Sqr Root{ ( 6x10^-5)x(6x10^-3)}
H+ = Sqr Root {36x10^(-8)}
as we know that Sqr root = power 1/2
so
H+ ={(6^2 x 10^(-8)} ^1/2
so by solving we will get
=6 x10(-4)
which is the right answer.
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