Chemistry, asked by ashraf663, 1 year ago

What would b
that would be [H+] of 0.006 M benzoic acid (K = 6 x10-5)

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Answers

Answered by ameyasaraf12
43

Answer:

Explanation:

I hope u will understand it

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Answered by nidaeamann
8

Answer:

answer is 2rd option that is 6x10^(-4)

Explanation:

As we know that

C = 0.006 M

K = 6 x 10(-5)

we know that to calculate H+ the formula is given below

H+ = Sqr\sqrt{K*c)}

so by placing values in it

H+ = Sqr root ( K*C)

by putting values

H+= Sqr Root{ ( 6x10^-5)x(6x10^-3)}

H+ = Sqr Root {36x10^(-8)}

as we know that Sqr root = power 1/2

so

H+ ={(6^2 x 10^(-8)} ^1/2

so by solving we will get

=6 x10(-4)

which is the right answer.

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