Question

What would be a³-6a²+12a÷a-2

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$(a-2)$ cannot divide $(a^3-6a^2+12a)$.

Step-by-step explanation:

Given division is $\frac{a^3-6a^2+12a}{a-2}$.

While solving these kind of divisions,

We need to look for an equation with higher degree either in the numerator or the denominator.

Here, the degree of the numerator is higher than the degree of the denominator.

Now, we need to factorize the highest degree polynomial.

The numerator is $a^3-6a^2+12a$.

Taking out $a$ as common, we get

$a(a^2-6a+12)$

Now we find the discriminant of the equation in the brackets, we get

Δ=$(-6)^2-4(12)(1)=36-48=-12<0$

There are no real roots.

So the division is not possible.