Question

what would be hydrolysis constant and degree of hydrolysis of 0.1m KCN solution . given that ka =6.2×10^-10​

Answer 1

Explanation:

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Answer 2

Answer:

ANSWER

CN

−

+H

2

O⇌HCN+OH

−

C

C(1−h) Ch Ch

K

h

=

C(1−h)

(Ch)(Ch)

Let 'h<<1'

So K

h

=Ch

2

We know that for a salt of weak acid and strong base K

h

=

K

a

K

w

So K

h

=1.38×10

−5

Ch

2

=1.38×10

−5

h=1.18×10

−2