Question

what would be its answer​

Answer 1

$(\frac{1}{x} + \frac{1}{y} )^3 = \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } + (3 \times \frac{1}{x} \times \frac{1}{y} )( \frac{1}{x} + \frac{1}{y} )$

=>

$(\frac{x + y}{xy})^3 = \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } + \frac{3}{xy} ( \frac{x + y}{xy} )$

Now, we will put the values

=>

$(\frac{a}{b} )^{3} = \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } + \frac{3}{b} ( \frac{a}{b} )$

=>

$(\frac{a}{b} )^{3} = \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } + \frac{3a}{ {b}^{2} }$

=>

$\frac{ {a}^{3} }{ {b}^{3} } - \frac{3a}{ {b}^{2} } = \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} }$

=>

$\frac{ {a}^{3} {b}^{3} - 3a {b}^{3} }{ {b}^{5} } = \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} }$

=>

$\frac{{b}^{3} ( {a}^{3} - 3a)}{ {b}^{5} } = \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} }$

=>

$\frac{ {a}^{3} - 3a }{ {b}^{2} } = \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} }$

=>

$\frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } = \frac{ {a}^{3} - 3a}{ {b}^{2} }$

It is very hard to write equations in BRAINLY.

$<marquee >Very Hard!!!!!!$