what would be new resistance if length of conductor is doubled and thickness is halved ?
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If you halve the 'thickness' of a circular conductor, the cross-sectional area (CSA) will be one quarter of what it was. This means that the resistance will increase by a factor of 4 (X4). If you now double its length, the resistance will only double (X2). Overall, the resistance will be 8 times what it was.
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Answer:
If you halve the 'thickness' of a circular conductor, the cross-sectional area (CSA) will be one quarter of what it was. This means that the resistance will increase by a factor of 4 (X4). If you now double its length, the resistance will only double (X2). Overall, the resistance will be 8 times what it was.
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