Question

What would be the amount under compound interest ones. 9950 at the end of 2 years at the rate of 20% per annum? ​

Answer 1

Given that : -

• princepal = 9950
• time = 2 years
• rate of interest = 20%per annum

We have to calculate: -

• the amount under compound interest

Need formulas

$\longmapsto \sf Amount (A) = princepal \bigg\lgroup 1+\dfrac{R}{100}\bigg \rgroup^n$

Solution : -

Given data : - princepal = 9950 ,time = 2years and rate of interest = 20% .we know that ,

$\sf Amount (A) = princepal \bigg\lgroup 1+\dfrac{R}{100}\bigg \rgroup^n$

$\qquad \blue{\underline{\underline {\large \bf {\red{putting \: value \: in \: formula : - - }}}}}$

$\longrightarrow \sf Amount (A) = 9950 \bigg\lgroup 1+\dfrac{20}{100}\bigg \rgroup^2 \\ \\ \\\longrightarrow \sf Amount (A) = 9950 \bigg\lgroup 1+\dfrac{ \cancel{20}}{ \cancel{100}}\bigg \rgroup^2 \\ \\ \\ \longrightarrow \sf \: Amount (A) = 9950 \bigg\lgroup 1+\dfrac{{1 \cancel0}}{ {5 \cancel0}}\bigg \rgroup^2 \\ \\ \\ \longrightarrow \sf \: Amount (A) = 9950 \bigg\lgroup 1+\dfrac{{1 }}{ {5 }}\bigg \rgroup^2 \\ \\ \\ \longrightarrow \sf \: Amount (A) = 9950 \bigg\lgroup \dfrac{{6 }}{ {5 }}\bigg \rgroup^2 \\ \\ \\ \longrightarrow \sf \: Amount (A) = \cancel{9950 }\times \dfrac{{6 }}{ \cancel { 5 }} \times \dfrac{6}{ \cancel5} \times \dfrac{6}{ 5} \\ \\ \\ \longrightarrow \sf \: Amount (A) = { 398 } \times \frac{6 \times 6 \times 6}{5} \\ \\ \\ \longrightarrow \sf \: Amount (A) = 398 \times \dfrac{216}{5} \\ \\ \\ \longrightarrow \sf \: Amount (A) = \frac{85968}{5} \\ \\ \\ \red{\frak{\longrightarrow \: Amount (A) = 17193 .6}}$

$\pmb{{ \pink{Hence }\: \blue{ compound \: interest be \: \tt17193.6}}}$