what would be the apparent weight of an iron block of size 5x5x5cm when completely immersed in water•density of water is 7.8g/cc
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Weight of iron block in air = density * volume = 5 g/cm³ * 125 cm³ = 625 grams
As the density of iron is more than the density of water, it sinks or gets submerged totally in water. We use the Archimedes law.
Buoyancy force = weight of water displaced
= volume of iron block * density of water
= 125 cm³ * 1 g/cm³ = 125 grams
Apparent weight = weight in air - buoyancy force
= 625 - 125 = 500 grams
Hope it helps
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As the density of iron is more than the density of water, it sinks or gets submerged totally in water. We use the Archimedes law.
Buoyancy force = weight of water displaced
= volume of iron block * density of water
= 125 cm³ * 1 g/cm³ = 125 grams
Apparent weight = weight in air - buoyancy force
= 625 - 125 = 500 grams
Hope it helps
Mark me as brainlist
shraddhasoudagar77:
how to do it..
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