What would be the combinations of four resistors of 2 ohm, 4 ohm, 6 ohm and 12 ohm to get equivalent resistance of 5.3 ohms and also of 4.5 ohms.
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Given : R1=2Ω R2=4Ω R3=6Ω
Parallel combination :
Equivalent resistance Rp1=R11+R21+R31
Rp1=21+41+61
⟹ Rp=1112Ω
Series Combination :
Equivalent resistance Rs=R1+R2+R3=2+4+6=12Ω
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