What would be the compound interest accrued on an amount of rs 9000 at the rate of 11 pcpa in two years?
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Given Principal Amount= P= 9000
Rates of interest Per annum= i =11%
Time= n =2years
Compound Interest = P[ (1+i)^n - 1]
=9000[ (1+11/100)^2 - 1]
=9000[(1 + 0.11)^2 -1]
=9000[ (1.11)^2 - 1]
=9000[1.221 - 1]
=9000[0.221]
=1989 is the Compound Interest...
Then compounded Amount = Principal Amount + Compound Interest
=9000 + 1989 =10989 is the Compounded amount
Rates of interest Per annum= i =11%
Time= n =2years
Compound Interest = P[ (1+i)^n - 1]
=9000[ (1+11/100)^2 - 1]
=9000[(1 + 0.11)^2 -1]
=9000[ (1.11)^2 - 1]
=9000[1.221 - 1]
=9000[0.221]
=1989 is the Compound Interest...
Then compounded Amount = Principal Amount + Compound Interest
=9000 + 1989 =10989 is the Compounded amount
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