Question

what would be the compound interest obtained on an amount of Rs.12,000 at the rate of the 9% p.c.p.a for 3 years (rounded off to two digits after decimal​

Answer 1

$\bullet \: \: \textsf{ \textbf{Correct option is B \underline \red{Rs. 3540.348}}} \: \: \bigstar$

Given:

• $\mathrm{P}= \bf12000$
• $\mathrm{R}= \bf9 \%$
• $\mathrm{F}=\mathrm{n}= \bf3 \: year$

To Find :-

• compound interest

Formula :-

$† \:\underline{ \boxed{ \tt{ \red{{A}={P}\left(1+\dfrac{{R}}{100}\right)^{{n}}}}}}$

Solution :-

$⇝ \sf{12000\left(1+\dfrac{9}{100}\right)^{3}} \\ \\⇝ \sf{12000\left(\frac{109}{100}\right)^{3}} \\ \\⇝ \sf{12000 \times \dfrac{109}{100} \times \dfrac{109}{100} \times \dfrac{109}{100}} \\ \\⇝ \underline{\boxed{\textsf{ \textbf{ \purple{{A} \: = \: 15540.348}}}}}$

$\bigstar \: \textsf{ \textbf{C.I. = \: A \: - \: P}} \\ \\⇢ \sf{C.I. =15540.348-12000} \\ \\⇢ \underline{ \boxed{ \tt{ \green{C.I = Rs. 3540.348}}}}$

Hence option (B) is the correct option