Question

What would be the denominator after rationalising 1/(7+3√2) ​

Answer 1

Step-by-step explanation:

$\frac{1}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} }$

$= \frac{7 - 3 \sqrt{2} }{7 - 18}$

$= \frac{7 - 3 \sqrt{2} }{ - 11}$

Answer 2

Answer:

1/7+3√2

=1/7-√18

=1/7-√18×7+√18/7+√18

=1/49-18×7+√18

=7+√18/31

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