Math, asked by Naidubabu5802, 7 hours ago

What would be the denominator after rationalizing 1 / ( 2√5-√3 ) ?

Answers

Answered by Anonymous
3

 \frac{1}{2 \sqrt{5} -  \sqrt{3}  }  \\  \\  =  \frac{1}{2 \sqrt{5} -  \sqrt{3}  }  \times  \frac{2 \sqrt{5}  +  \sqrt{3} }{2 \sqrt{5}  +  \sqrt{3} }  \\  \\  =  \frac{2 \sqrt{5}  +  \sqrt{3} }{( {2 \sqrt{5}) }^{2}  -  {( \sqrt{3}) }^{2} }  \\  \\  =  \frac{2 \sqrt{5} +  \sqrt{3}  }{4 \times 5 - 3}  \\  \\  =  \frac{2 \sqrt{5} +  \sqrt{3}  }{20 - 3}  \\  \\  =  \frac{2 \sqrt{5} +  \sqrt{3}  }{17}

After rationalizing the denominator will be 17

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