Question

What would be the denominator after rationalizing 7/(5√3 - 5√2)

Answer 1

$\frac{7}{5\sqrt{3}-5\sqrt{2} } *\frac{5\sqrt{3}+5\sqrt{2}}{5\sqrt{3}+5\sqrt{2} } \\\\=\frac{35\sqrt{3}+35\sqrt{2} }{(5\sqrt{3})^2-(5\sqrt{2})^2 } \\\\=\frac{35\sqrt{3}+35\sqrt{2} }{(25*3)-(25*2) } \\\\=\frac{35\sqrt{3}+35\sqrt{2} }{75-50}\\ \\=\frac{35\sqrt{3}+35\sqrt{2} }{25}\\\\=\frac{5(7\sqrt{3}+7\sqrt{2}) }{25}\\\\=\frac{7\sqrt{3}+7\sqrt{2} }{5}$

Hence, denominator is 5 .

Answer 2

Answer:

do rationalisation

Step-by-step explanation:

7/(5√3-5√2)×(5√3+5√2)/(5√3+5√2)

35√3+35√2/75-50

35(√3+√2)/25

7(√3+√2)/5 answer..