What would be the denominator after rationalizing 7/(5√3 - 5√2)?
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rationalizing= 7/(5√3 - 5√2)
7 x (5√3 + 5√2)/(5√3 - 5√2)(5√3 + 5√2)
35√3 +35√2/(5√3)^2-(5√2)^2
35√3 +35√2/75-10
35√3 +35√2/65
hence the denominator is 65
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