Question

What would be the denominator after rationalizing 7/(5√3 - 5√2)? *​

Answer 1

Answer:

Here, the denominaror would be 5 after rationalising and the answer is=7(root3+root2)/5.

Step-by-step explanation:

According to question,

7/(5root3-5root2)=

7/5(root3-root2)=[After taking 5 as common in both]

=[7/5(root3-root2)]×5(root3+root2/root3+root2)

=On multiplying both to each other, we get

=35(root3+root2)/25[(root3)^2-(root2)^2]

=35(root3+root2)/25(3-2)

=35(root3+root2/25

=[7(root3+root2)]/5=[As, 25 and 35 both are divisible by 5]

So, the answer is =[7(root3+root2)]/5.

Thank you.