Math, asked by kiranaga1979, 5 months ago

what would be the denominator after rationalizing 7/(5 root 3 - 5root 2)

Answers

Answered by PeeyushVerma
34

Answer = 25

Refer the attachment for the answer

Attachments:
Answered by Vimalraj17
0

Answer:

 \frac{7( \sqrt{3}  +  \sqrt{2} )}{5}

Step-by-step explanation:

 \frac{7}{5 \sqrt{3}  - 5 \sqrt{2} }

 =  \frac{7}{5( \sqrt{3}  -  \sqrt{2} )}

Rationalise the denominator by multiplying both numerator and denominator by (√3+√2)

  =  \frac{7 \times ( \sqrt{3}  +  \sqrt{2} )}{5( \sqrt{3} -  \sqrt{2}  ) \times ( \sqrt{3} +  \sqrt{2} ) }

 =  \frac{7( \sqrt{3 } +  \sqrt{2}  )}{5(3 - 2)}

 =  \frac{7( \sqrt{3} +  \sqrt{2} ) }{5(1)}

 =   \frac{7( \sqrt{3}  +  \sqrt{2} )}{5}

Hope this answer and explanation help you...

Similar questions