Question

What would be the equation of the line, which intercepts x-axis at -5 and is perpendicular to the line y = 2x + 3?

Answer 1

2x-y+3=0

Any line perpendicular to this line

will be of the form

-x-2y + k = 0

it passes through (-5,0)

5 + k=0
k = -5

The required line is


x + 2y + 5 = 0