Question

What would be the equivalent conductivity of a cell in which 0.5 N
salt solution offers a resistance offers 40 ohm whose electrodes
ara 2 cm apart and 5cmº in area?​

Answer 1

Given:

Normality, N = 0.5 N

Resistance, R = 40 ohm

Length, l = 2 cm

Area, A = 5 cm²

To Find:

The equivalent conductivity of the cell.

Calculation:

- The conductivity of the cell is given by:

κ = l / AR

⇒ κ = 2 / (5 × 40)

⇒ κ = 0.01 S/cm

- The equivalent conductivity is given as:

Λeq = (κ × 1000) / N

⇒ Λeq = (0.01 × 1000) / 0.5

⇒ Λeq = 20 S cm²/ eq.

- So, the equivalent conductivity of the cell is 20 S cm²/ eq.