Question

what would be the final temperature mixtures if 40 grams of water at 20 degrees c mixed with 60 grams of water at 30 degrees c​

Answer 1

Answer:

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Answer 2

26°c

Explanation:

M1 = 40gm. T1 = 20°c

M2 = 60gm. T2 = 30°c

Final Temperature Of Mixtures

T=(M1 T1) +( M2 + T2) / M1 + M2

=40×20+60×30/40+60

=2600/100 = 26°C