What would be the height of a rectangular
solid with square base of area 25 square
units and having volume equal to this
cylinder?
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Answered by
1
Answer: 5.65units.
Step-by-step explanation:
Let the length be L, breadth be B and the height be H of the rectangle. According to the question the rectangle has a square base whose area is 25 square units therefore the value of lenght and breadth will be equal
Side²=25
Side = 5unit
The volume of the rectangle is equal to the volume of the cylinder. Therefore the volume of the cylinder is
π×r²×h
π×3²×5
141.37
Volume of the rectangle=L×B×H
141.37=5×5×H
H= 5.65units
Answered by
1
Answer:
volume of cylinder =π * 3^2* 5
Now if x be length and breadth of square base. and y be the height of the rectangular solid.
=> x^2*y= volume of cylinder = π * 3^2* 5
Here x^2= 25 square unit
=> y = π * 3^2* 5 /25 = 9π/5 = 5.65 unit
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