Question

What would be the last term of an arithmetic progression with 10 terms whose second term is -23 and the third term is -35? *

1 point

Option 1: 119

Option 2: -107

Option 3: -650

Option 4: -12

​

Answer 1

a2 = -23

a3 = -35

Therefore, difference d = -35 - (-23) = -12

First term

a1 = -23 - (-12) = -23 + 12

a1 = -11

an = a + (n - 1) d [a = 1st term]

a10 = -11 + (10 - 1) -12

= -11 + 9 × -12

a10 = -119

The option -119 is not given in the list. Kindly verify the same.