What would be the mass, in grams, of 1.505 x 10^23 molecules of carbon disulfide?
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Answer:
To Find :
The mass, in grams, of 1.505 \times 10^{23}1.505×10
23
molecules of carbon disulfide (CS₂).
Solution :
Molecular mass of CS₂ = 76 gm/mol .
It means that mass of 6.022 \times 10^{23}6.022×10
23
molecules of CS₂ is 76 gm/mol.
Let, mass of 1.505 \times 10^{23}1.505×10
23
molecules of carbon disulfide (CS₂) is x.
So,
\begin{gathered}x= 76\times \dfrac{1.505 \times 10^{23}}{6.022\times 10^{23}}\\\\x = 76 \times \dfrac{1.505}{6.022}\\\\x = 19 \ gm\end{gathered}
x=76×
6.022×10
23
1.505×10
23
x=76×
6.022
1.505
x=19 gm
Therefore, the mass in gram is 19 gm.
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