Chemistry, asked by eeshazahra, 5 hours ago

What would be the mass, in grams, of 1.505 x 10^23 molecules of carbon disulfide?

Answers

Answered by vinodkumarvk035
3

Answer:

To Find :

The mass, in grams, of 1.505 \times 10^{23}1.505×10

23

molecules of carbon disulfide (CS₂).

Solution :

Molecular mass of CS₂ = 76 gm/mol .

It means that mass of 6.022 \times 10^{23}6.022×10

23

molecules of CS₂ is 76 gm/mol.

Let, mass of 1.505 \times 10^{23}1.505×10

23

molecules of carbon disulfide (CS₂) is x.

So,

\begin{gathered}x= 76\times \dfrac{1.505 \times 10^{23}}{6.022\times 10^{23}}\\\\x = 76 \times \dfrac{1.505}{6.022}\\\\x = 19 \ gm\end{gathered}

x=76×

6.022×10

23

1.505×10

23

x=76×

6.022

1.505

x=19 gm

Therefore, the mass in gram is 19 gm.

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