What would be the molality of a 100 gm solution Containing 10 gm NaCl ?
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Considering the density of water as 1 g/ ml, the volume of water is 720 ml.
Considering the density of water as 1 g/ ml, the volume of water is 720 ml.Also on dissolving 10g NaCl, there will not be considerably change in the volume of the solution. So the in 720 ml.of the Solution,10 g of NaCi is present.
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Molality = number of moles of solute / mass of solvent(kg)
number of moles = mass / molar mass
For NaOH, mass = 10g,
molar mass = 40 g/mol
water, mass = 100g = 0.1 kg
Thus, molality= 10/40×0.1
=2.5 m
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