Question

What would be the osmotic pressure at 25 c of an aqueous solution containing 1.95 g of sucrose?

Answer 1

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Brainly.in

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Secondary SchoolChemistry 5 points

What would be the osmotic pressure at 25°C of an aqueous solution containing 1.95g of sucrose present in 150 ml of solution?

Ask for details Follow Report by Sayyadsanaanjum 15.11.2018

Answers

prafullsupe78

prafullsupe78 Expert

Hi mate.

Thanks for asking this question,

Here is your answer,

Given :

T = 25c = 298k

V = 150 ml.

n = w/m = 1.95 / 342 = 0.005 moles.

R = 8.314 J/k.mol.

\pi \: =

We know that,

\pi \: v \: = \: n \: r \: t

Therefore,

\pi \ \times 150 \: = \: 0.005 \times 8.314 \times 298

\pi \: \times 150 = \: 5 \times {10}^{? - 3 } \times 8.314 \times \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 298

\pi \: = \: 0.33 \times {10}^{? - 2} \times 2477.5

\pi \: = \: 3.3 \times {10}^{? - 3} \times 2477.5

\pi \: = 8175.98 \: \times {10}^{ - 3} pa.

Answer 2

T=25 C

=298 K

molar mass of sucrose=342 gm

weight of sucrose taken=1.95 gm

let V=1 L   (since volume isn't given so i have taken it to be 1 L)

i=1

R=0.082

π=iCRT

=1*1.95/342*300*0.082

=0.14 atm

Hope this helps.