What would be the pH of a solution in which [H+] = 10^(-7) m/L at 25°C?
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In pure water or a neutral solution the [H + ] = 1.0 × 10 -7 M. Substituting into the pH expression:
pH = -log[1.0 × 10 -7 ] = -(-7.00) = 7.00
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