Question

what would be the pH of an aqueous solution of sulphuric acid which is 5×10-5 in concentration​

Answer 1

4 will be the  pH of an aqueous solution of sulphuric acid which is 5×10-5 in concentration​

Explanation:

pH = - log (H⁺ )                      ...........eq i

NOW H₂SO₄     =     2 H⁺ + SO₄⁻²

I MOL OF  H₂SO₄ has 2 H⁺ ION

SO THE NO OF  H⁺ ION = 2 * H₂SO₄

                                          = 2*5*10⁻⁵

                                            = 10⁻⁴

now using eq 1 we get :

                        = - log (H⁺ )

                        = - log (10⁻⁴ )

                        = 4

                               

Answer 2

Answer:

0.005 Molar of aqueous solution sulphuric acid is present, Concentration of protons in acid is written as

[H

+

]=0.005

pH=−log([H

+

])=−log(0.005)=2.301

pH=2.301 approximately 2.

This is the answer

Explanation:

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