Physics, asked by riajivani, 4 months ago

what would be the pressure of water at depth of 200 cm the density of water is 7000 kg / m^3 *

140000 Pa
14000 Pa
35 Pa
3500 Pa

Answers

Answered by purabkumar830
0

Answer:

The gauge pressure at any depth is given by,

P

g

=ρgh

Given, the atmospheric pressure to be P

o

=1.013×10

5

Pa

The pressure at this depth will be,

P=P

o

+P

g

= 1.013×10

5

+1.03×10

3

×10×200

= 21.2×10

5

Pa

Answered by mananphymath
2

Answer:

140000 Pa

Explanation:

Pressure of substance at some depth is (Density of substance x acceleration due to gravity x depth)

Density = 7000 kg / m^3

Acceleration due to gravity  = 9.8 m / s^2 = 10 m / s^2 approx.

Depth = 200 cm = 2 m

Pressure = 7000 x 10 x 2 N/m = 140000 N/m = 140000 Pa

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