Physics, asked by sumitashrma, 1 year ago

what would be the radius of 2nd excited State in Li+2 ion ?

Answers

Answered by Anonymous
21

we know that the radius of any orbit of any hydrogen like species and hydrogen is given by 52.9 pm × n²/Z

where Z is the Atomic number and  and n is the respective orbit

Li²⁺ is hydrogen like species and the Atomic number of Lithium is 3

In the 1st excited state of Li²⁺ the electron jumps from n= 1 to n = 2 and the in the 2nd excited state of Li²⁺ the electron jumps from n = 2 to n = 3. so in the 2nd excited state the electron is present in the orbit, n = 3

substituting the above values in the radius equation we get:

r₂ = 52.9 pm × 3²/3 = 158.7 pm = 1.587 angstroms

where pm is picometres = 10⁻¹² metre and one angstrom = 10⁻¹⁰ metre



sumitashrma: the ans. is in Angstrom and my approx. ans. is 1.587 angstrom and the correct ans. is 1.51angstrom
Anonymous: yes the answer is 1.587 angstrom. .2nd excited state means n = 3. . .i thought the electron is second orbit. .i need to correct this one too.
Anonymous: i corrected it!
sumitashrma: ooo
sumitashrma: so my ans is correct or not
Anonymous: did i commit a mistake again?
sumitashrma: which mistake
Anonymous: i mean by going your expression. .ooo. .i thought i made a mistake again. .so i asked.
sumitashrma: i said it simply
sumitashrma: ok thanks
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